5x^2-4x-672=0

Solution for 5x^2-4x-672=0 equation:

5x^2-4x-672=0

a = 5; b = -4; c = -672;
Δ = b2-4ac
Δ = -42-4·5·(-672)
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13456}=116$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-116}{2*5}=\frac{-112}{10}
=-11+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+116}{2*5}=\frac{120}{10}
=12
$